(2x^2+10x-28)/(4x+28)

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Solution for (2x^2+10x-28)/(4x+28) equation: 


D( x )

4*x+28 = 0

4*x+28 = 0

4*x+28 = 0

4*x+28 = 0 // - 28

4*x = -28 // : 4

x = -28/4

x = -7

x in (-oo:-7) U (-7:+oo)

(2*x^2+10*x-28)/(4*x+28) = 0

2*x^2+10*x-28 = 0

2*(x^2+5*x-14) = 0

x^2+5*x-14 = 0

DELTA = 5^2-(-14*1*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)-5)/(1*2) or x = (-81^(1/2)-5)/(1*2)

x = 2 or x = -7

2*(x+7)*(x-2) = 0

(2*(x+7)*(x-2))/(4*x+28) = 0

( x+7 )

x+7 = 0 // - 7

x = -7

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -7} 

x = 2

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